VHDL coding tips and tricks: Simple 4 : 1 multiplexer using case statements

Saturday, March 27, 2010

Simple 4 : 1 multiplexer using case statements

   Here is the code for 4 : 1 MUX using case statements.The module contains 4 single bit input lines and one 2 bit select input.The output is a single bit line.

library IEEE;

entity multiplexer4_1 is
port (
      i0 : in std_logic;
      i1 : in std_logic;
      i2 : in std_logic;
      i3 : in std_logic;
     sel : in std_logic_vector(1 downto 0);
     bitout : out std_logic
end multiplexer4_1;

architecture Behavioral of multiplexer4_1 is

case sel is
  when "00" => bitout <= i0;
  when "01" => bitout <= i1;
  when "10" => bitout <= i2;
  when others => bitout <= i3;
end case;
end process;

end Behavioral;

The testbench code used for testing the code is given below:

  LIBRARY ieee;
  USE ieee.std_logic_1164.ALL;

  ENTITY testbench IS
  END testbench;

  ARCHITECTURE behavior OF testbench IS
          SIGNAL i0,i1,i2,i3,bitout :  std_logic:='0';
          SIGNAL sel :  std_logic_vector(1 downto 0):="00";
    UUT : entity work.multiplexer4_1 port map(i0,i1,i2,i3,sel,bitout);

     tb : PROCESS
            sel <="00";
            wait for 2 ns;
            sel <="01";
            wait for 2 ns;
            sel <="10";
             wait for 2 ns;
             sel <="11";
              wait for 2 ns;
            --more input combinations can be given here.
     END PROCESS tb;


     The simulated testbench waveform is shown below:

  The code was synthesized using XILINX ISE XST . The RTL schematic of the design is shown below.

Note :- Use RTL Viewer to get a closer look on how your design is implemented in hardware.


  1. can you please explain the dataflow model...

  2. it's very easy but how I write code for 8 bits multiplexer?
    problem is:
    a and b 8 bot input, c is 2 bit input , D is 8bit output if c="00" output A, c="01" output B, c="10" output D, c="11" output Z
    help me how I write Its code

  3. What is the difference between your architecture code and the following one from synthesis point of view?
    In case of pure combinational logic (like the described multiplexer) why a process with all the inputs in the sensitivity list should be used instead of the version below?

    maybe its the same, or maybe I miss some important difference between the two different descriptions!

    architecture Behavioral of multiplexer4_1 is

    bitout <= i0 when sel="00" else
    i1 when sel="01" else
    i2 when sel="10" else
    i3 ;

    end Behavioral;

  4. actually your syntext is totally wrong...either use elsif.or use other architecture....

  5. programme vhdl d'un multiplexeur 4-1 en utilisant 2 demi multiplexeurs

  6. i am a beginner to vhdl..... Can u explain how i can see the rtl schematic in the form of AND , XOR..... i get them as mere boxes with corresponding inputs and outputs........